The Last Dance — HackTheBox

Description

The challenge provides a Python script that encrypts a known message and a secret flag using the ChaCha20 stream cipher. Both encryptions use the same key and the same nonce.

Analysis

ChaCha20 is a stream cipher. It generates a keystream based on a key and a nonce. The ciphertext is produced by XORing the plaintext with this keystream: C = P ⊕ KS

If the same key and nonce are used to encrypt two different messages ($P_1$ and $P_2$), the same keystream ($KS$) is generated for both:

1. $C_1 = P_1 ⊕ KS$
2. $C_2 = P_2 ⊕ KS$

Since we know $P_1$ (the known message) and $C_1$ (its ciphertext), we can recover the keystream: $KS = C_1 ⊕ P_1$

Once we have the keystream, we can decrypt the flag ($P_2$) using its ciphertext ($C_2$): $P_2 = C_2 ⊕ KS$

Solution

source.py

from Crypto.Cipher import ChaCha20
from secret import FLAG
import os

def encryptMessage(message, key, nonce):
    cipher = ChaCha20.new(key=key, nonce=iv)
    ciphertext = cipher.encrypt(message)
    return ciphertext

if __name__ == "__main__":
    message = b"Our counter agencies have intercepted your messages and a lot "
    message += b"of your agent's identities have been exposed. In a matter of "
    message += b"days all of them will be captured"

    key, iv = os.urandom(32), os.urandom(12)

    encrypted_message = encryptMessage(message, key, iv)
    encrypted_flag = encryptMessage(FLAG, key, iv)

    data = iv.hex() + "\n" + encrypted_message.hex() + "\n" + encrypted_flag.hex()
    # ... write to out.txt

solve.py

#!/usr/bin/env python3

def xor(a, b):
    return bytes([x ^ y for x, y in zip(a, b)])

...